I got BTL3194450-494 (FP#74/BP#56) replacing BTM5069372-416 (74/56) (from a brick) , but there was a little surprise: I found BTL3199002 (74/56) in the place of BTL3194469. A replacement in a replacement, but in the same range.... Strange... And more, the position numbers were the same, telling me that this range has a skip number at least 6000.
If I'm remember well, the combination FP#74/BP#56 is one of those found in the so-called "mini-ream", isn't it?...
Question: has some had already found a such occurence (replacement in replacement) ?...
Hi, thanks for this post. This is a very important thing to address.
a) Replacements within a replacement? Yes this can happen.
b) These would all be from column 5 of a sheet, according to the current standard matrix. Having BTL replacements that are from bricks 5000 apart (but replaced into one brick) tells us two things:
1) It is indeterminable if they are SNRs or sheet replacements.
If SNRs, the it would be likely a serial number span of 20,000. That's right, 20,000.
the LCM of 5 and 4 (which is what the superbricks come packaged in) is 20. No one has yet to confirm a find where the superbrick had a first brick that started with anything other than a perfect multiple of 4.
Reasoning: Because there is 5 columns, one would have to count all 5 bricks, in each row 3194 and 3199 = 10 bricks. We know that if the two ranges here are SNRs, then it is impossible for the remaining 4 positions of the row to be SHEET replacements. They are either NOT replacements at all (would have to study neighboring bricks) or they are mini-ream replacements. Assuming the neighbouring bricks show is that the two ranges are DISJOINT, then we have two distinct ranges. However, if the study of adjacent bricks shows them to be joint (see my posts on ALL $20s, still unconfirmed, arg!...), then the minimum would be 20,000.
2) If SNR OR Sheet replacement (5000 mini sheet):
If we include the two rows, totalling 10 bricks, then what that does is stagger the super brick package. It would imply that since 10 =
2 module 4, there would be a staggering within the superbrick bag packages by
2 brick positions (or a 2000 serial number count).
HOWEVER: There has yet to be a confirmed finding of any super-brick package to ever be found with this type of staggering. Meaning, the staggering must continue to some point such that the staggering brings itself back to a point of
0 modulo 4.
As a result of this, we know that simply 10 bricks of replacements is not possible (since it throws off the super brick packages). The lowest number of bricks needed in order to resume the 0 modulo 4 package set-up, would be 20 bricks of replacements, or a range of 20,000.
c) This special case is applicable in this case because the replacements and the mother brick are all from the mini-ream. Just like my find with the ALL Journey $20s, which have stil to this day gone unconfirmed.
*****
To make a direct call on this situation (SNR or Sheet), the data set for adjoining bricks in nearly every direction would need to be closely analyzed.
If this reads like a bunch of greek, just email me and I will try to help straighten things out. It's late and I can't sleep.